Searched refs:vararg_with_default_impl (Results 1 – 2 of 2) sorted by relevance
1015 vararg_with_default_impl(PyObject *module, PyObject *a, PyObject *args, in vararg_with_default_impl() function
2071 vararg_with_default_impl(PyObject *module, PyObject *a, PyObject *args,2100 return_value = vararg_with_default_impl(module, a, __clinic_args, b); in vararg_with_default()