Lines Matching full:cpu1

62 - work_per_hz(CPU1) = W/2
68 - capacity(CPU1) = C/2
70 To draw the parallel with Arm big.LITTLE, CPU0 would be a big while CPU1 would
81  CPU1 work ^
87 work W in T units of time. On the other hand, CPU1 has half the capacity of
97 - max_freq(CPU1) = 2/3 * F
102 - capacity(CPU1) = C/3
112                             workload on CPU1
113  CPU1 work ^
191 - capacity(CPU1) = C/3
201  CPU1 work ^
209 - duty_cycle(p) == 75% if p runs on CPU1 at its maximum frequency
382   capacity(CPU1) = C / 3
391                            workload on CPU1