Lines Matching +full:0 +full:x10002

23 from an address that is not evenly divisible by N (i.e. addr % N != 0).
24 For example, reading 4 bytes of data from address 0x10004 is fine, but
25 reading 4 bytes of data from address 0x10005 would be an unaligned memory
41 divisible by N, i.e. addr % N == 0.
94 starting at address 0x10000. With a basic level of understanding, it would
97 structure, i.e. address 0x10002, but that address is not evenly divisible
159 	return fold == 0;
163 	return ((a[0] ^ b[0]) | (a[1] ^ b[1]) | (a[2] ^ b[2])) == 0;
169 able to access memory on arbitrary boundaries, the reference to a[0] causes
172 Think about what would happen if addr1 was an odd address such as 0x10003.
252 here is powerpc which defines NET_IP_ALIGN to 0 because DMA to unaligned